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42p^2=14/3
We move all terms to the left:
42p^2-(14/3)=0
We add all the numbers together, and all the variables
42p^2-(+14/3)=0
We get rid of parentheses
42p^2-14/3=0
We multiply all the terms by the denominator
42p^2*3-14=0
Wy multiply elements
126p^2-14=0
a = 126; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·126·(-14)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*126}=\frac{-84}{252} =-1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*126}=\frac{84}{252} =1/3 $
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